Re: Hole in one odds from Yahoo news story
[ QUOTE ]
If we assume independence it should be :
(1/5001)^2*5000/5001 + 5000/5001*(1/5001)^2*5000/5001 +
(5000/5001)*(1/5001)^2 = 0.0000001199
ie ppq,qppq,qpp
[/ QUOTE ]
Since the statement and question don't mention anything about the other two players, I dont see anything wrong with using -
(1/5001)^2*3 = 0.00000011995201
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