Re: Hole in one odds from Yahoo news story
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ncray - shouldn't that be:
(1/5001)^2 * (5000/5001)^2 * 6 (about 2.2 * 10^-7 so 1 in 4 million)
since 4 chose 2 = 6
This works out to the average chance of a golfer in a 4-some of holing as somewhere around 1 in 10,000 instead.
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They were calculating the probability of two players in a foursome getting back-to-back aces. So, only three of the pairings qualify.
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