Re: New heads up poker game - best strategy?
I think I would take Jim's side. Choosing 2 from 8 cards means that he can choose the best from 28 possible starting hands (I know these are not independent, but still 28 is a lot). I suspect that (given the stack sizes that you specified) if he just jams every single hand, that he will be +ev. I will work out some math later on this - don't have the time right now. One way to think about this would be to model this with a [0,1]-game (as in Mathematics of Poker). Let's suppose that the largest number wins (I know this is the opposite to MOP) Now suppose that Jim gets dealt 28 uniformly distributed random numbers between 0 and 1 and can choose the largest of these to play against against your single uniformly distributed random number. His hand will be better than yours more than 97% of the time. That is a big edge! I'll try to work this out fully later
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