Re: Probability of a higher pocket pair
Yes Binions that would be a good approximation .
With AQ , the probability against 9 other opponents that you will be dominated is approximately :
1-[(1225-24)/1225]^9=16.31%
With AK versus A's or K's it is :
9c1*6/50c2 -9c2*3*3*2/50c2/48c2= 4.36%
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