Re: raising with draws - how much FE needed?
Yup I just checked it over and the formula is correct .
It's a neat way to calculate the percentage of times one needs to fold for a shove to be positive EV .
Here is the formula if you have 6 outs , or about a 25% chance of winning .
x(P+B+S)+1/4(1-x)(2S+P) > S
4x(P+B+S) + 2S+P -x(2S+P)>4S
x[2S+3P+4B] >2S-P
x>(2S-P)/(2S+3P+4B)
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