[Mook]

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the blocking bet may well be -EV in that situation, but it may still be your best play

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This is impossible. EV(checkfold) = 0

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OK. If we're being mathematically precise: A blocking bet may well be -EV but still have the greatest overall expectation of any possible play (including check-folding).

I hope you're debating the semantics, not the mathematics, because the latter is indisputable. There are many times in NLHE, as noted above, when checking and value-betting each have a lower overall expectation than betting, say, 1/4 to 1/3 of the pot, even when few (if any) worse hands will call and few (if any) better hands will fold.

Mook