Re: Probability question
12c5 * 7!/12! double counts some combos, but the answer is probably pretty close. I think you probably need some sort of inclusion exclusion.
Suppose the 5 chosen were 1, 2, 3, 4, 5, and 6-10 ended up being in the same order as well. This is double counted when you choose 6-10, and 1-5 just happen to be in the same order.
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