Re: Probability question
Take a string of 12 numbers :
1_2_3_4_5_6_7_8_9_10_11_12
There are 12! different ways to arrange these numbers .
Assume that the first 5 are in the same order as last year . Again there is only 1 way that can happen . Now we can arrange the 7 numbers 6 through 12 which gives us an additional 7! combos .
12c5*7!/12! = 0.00833 or just under 1 % .
b) E(x)=1/12*(1+2+3+4+...12) = 6.5
where x takes on the values of your ranking order in the draft .
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