Re: odds of set over set
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The probability that both pairs flop sets is:
2*2*44/C(48,3) =~ 1.02%
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Wow thanks man. Haha, for some stupid reason I thought the math would be something like 0.12 x 0.12 = 1.5%, and set A being higher than set B would be that number divided in two, 0.75%.
Still though, can I use your number - 1.02 - and devide that by 2 (= about 0.5 %) to get the odds of one spesific set being higher than the another if two players with PPs are seeing a flop? (of course it would be a matter of the texture of the flop and you would know if you flopped the highest set, but just theoreticly speaking)
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