Re: prob of beating N opponents given prob of beating 1 opponent
respondant is correct.... of course, your odds of beating the second guy won't be same as beating the first, might be ok for an assumption though in certain circumstances.....
nice thing is that if you have TT, and one opponent has AK and another AQ, then their sharing of the aces cuts down on their cumulative winning percentage. if they have QJ and AK against your TT, then that's a big problem.
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