Re: probability question
Hi PairTheBoard,
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(a U b U d U e) intersect (a U c) is not equal to a.
In fact, under aaron's conditions they are equal iff P(a)=.2
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A very insightful point. Thank you. I'll fill the proof you left out by mentioning that under Aaron's conditions, aUc = c, so
(a U b U d U e) intersect (a U c) = aUd as c contains all points in a and d, and is ME with bUd.
We know that aUd = .2 from equation 2) aUd U bUe = .8 with Aaron assuming bUe is ME with aUd and equal to .6. Therefore, this intersection = a only when p(d) = 0 and p(a) = .2.
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Regardless, your original conditions still imply that
P( (a U b U d U e) intersect (a U c) ) = .2
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Frankly, I'm getting rather bored with your simply stating that this is the case. You may be right, but "PairTheBoard said so" does not constitute a proof in my mind.
There is obviously confusion over this point, so if you can prove what you claim, why don't you just do it?
-eric
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