View Single Post
  #6  
Old 10-22-2006, 09:43 AM
elindauer elindauer is offline
Senior Member
 
Join Date: Jun 2003
Location: analyzing hand ranges
Posts: 2,966
Default Re: probability question

Hi PairTheBoard,

[ QUOTE ]
(a U b U d U e) intersect (a U c) is not equal to a.

In fact, under aaron's conditions they are equal iff P(a)=.2

[/ QUOTE ]

A very insightful point. Thank you. I'll fill the proof you left out by mentioning that under Aaron's conditions, aUc = c, so

(a U b U d U e) intersect (a U c) = aUd as c contains all points in a and d, and is ME with bUd.

We know that aUd = .2 from equation 2) aUd U bUe = .8 with Aaron assuming bUe is ME with aUd and equal to .6. Therefore, this intersection = a only when p(d) = 0 and p(a) = .2.



[ QUOTE ]
Regardless, your original conditions still imply that

P( (a U b U d U e) intersect (a U c) ) = .2

[/ QUOTE ]

Frankly, I'm getting rather bored with your simply stating that this is the case. You may be right, but "PairTheBoard said so" does not constitute a proof in my mind.

There is obviously confusion over this point, so if you can prove what you claim, why don't you just do it?

-eric
Reply With Quote