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jay_shark
Forum:
Probability
03-10-2007, 10:42 PM
Replies:
12
Discovered series result
Views:
97
Posted By
jay_shark
Re: Discovered series result
Ok I figured out another way to solve this .
The expression is equivalent to
{sum n=k to infinity}C(n,k)x^(n-k)*(1-x)^(k+1)=1
Suppose you have a bias coin with probability x of landing...
Forum:
Probability
02-17-2007, 03:24 PM
Replies:
12
Discovered series result
Views:
97
Posted By
jay_shark
Re: Discovered series result
Aaron your posts are always very insightful and I always look forward to what you have to say .
However , x+x*(1-x)+x*(1-x)^2+.... = x/(1-(1-x)) which is just a geometric series with first term x...
Forum:
Probability
02-16-2007, 09:49 AM
Replies:
12
Discovered series result
Views:
97
Posted By
jay_shark
Re: Discovered series result
I couldn't think of a probabilistic argument to show this .
Bruce , do you mind sharing to us your solution?
Forum:
Probability
02-14-2007, 07:15 PM
Replies:
12
Discovered series result
Views:
97
Posted By
jay_shark
Re: Discovered series result
Jason , there has to be a better way .
I always try to look for elegant solutions to complex problems . This one has a nice solution to it .
Forum:
Probability
02-14-2007, 06:34 PM
Replies:
12
Discovered series result
Views:
97
Posted By
jay_shark
Re: Discovered series result
This is my kind of problem .
It seems like a very interesting result and I haven't seen it anywhere .
I could be wrong but it looks as if this problem relates to gamblers ruin . Substitute x=q...
Showing results 1 to 5 of 5
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