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Search: Posts Made By: jay_shark
Forum: Probability 03-10-2007, 10:42 PM
Replies: 12
Views: 97
Posted By jay_shark
Re: Discovered series result

Ok I figured out another way to solve this .

The expression is equivalent to

{sum n=k to infinity}C(n,k)x^(n-k)*(1-x)^(k+1)=1

Suppose you have a bias coin with probability x of landing...
Forum: Probability 02-17-2007, 03:24 PM
Replies: 12
Views: 97
Posted By jay_shark
Re: Discovered series result

Aaron your posts are always very insightful and I always look forward to what you have to say .

However , x+x*(1-x)+x*(1-x)^2+.... = x/(1-(1-x)) which is just a geometric series with first term x...
Forum: Probability 02-16-2007, 09:49 AM
Replies: 12
Views: 97
Posted By jay_shark
Re: Discovered series result

I couldn't think of a probabilistic argument to show this .

Bruce , do you mind sharing to us your solution?
Forum: Probability 02-14-2007, 07:15 PM
Replies: 12
Views: 97
Posted By jay_shark
Re: Discovered series result

Jason , there has to be a better way .

I always try to look for elegant solutions to complex problems . This one has a nice solution to it .
Forum: Probability 02-14-2007, 06:34 PM
Replies: 12
Views: 97
Posted By jay_shark
Re: Discovered series result

This is my kind of problem .

It seems like a very interesting result and I haven't seen it anywhere .

I could be wrong but it looks as if this problem relates to gamblers ruin . Substitute x=q...
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