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-   -   40 Year Old Vs 65 Year Old American Hitting 90 (http://archives1.twoplustwo.com/showthread.php?t=557694)

David Sklansky 11-30-2007 01:35 AM

40 Year Old Vs 65 Year Old American Hitting 90
 
If you randomly choose a present day 40 year old American and a present day 65 year old, who is more likely to reach 90?

POKEROMGLOL 11-30-2007 02:01 AM

Re: 40 Year Old Vs 65 Year Old American Hitting 90
 
ill answer if you rate my dinner david

David Sklansky 11-30-2007 02:04 AM

Re: 40 Year Old Vs 65 Year Old American Hitting 90
 
You cooked me dinner?

POKEROMGLOL 11-30-2007 02:07 AM

Re: 40 Year Old Vs 65 Year Old American Hitting 90
 
http://forumserver.twoplustwo.com/showfl...=0#Post13180492

kevin017 11-30-2007 02:51 AM

Re: 40 Year Old Vs 65 Year Old American Hitting 90
 
these seem about equal, perhaps a small edge to the 65 year old.

ut2010 11-30-2007 02:57 AM

Re: 40 Year Old Vs 65 Year Old American Hitting 90
 
ugh not health and fitness too.

KingGordy 11-30-2007 03:26 AM

Re: 40 Year Old Vs 65 Year Old American Hitting 90
 
I choose the 65 year old.

AZK 11-30-2007 11:58 AM

Re: 40 Year Old Vs 65 Year Old American Hitting 90
 
40

Yobz 11-30-2007 12:52 PM

Re: 40 Year Old Vs 65 Year Old American Hitting 90
 
Would answers change if you say 20 year old versus 65 year old?

Clearly this boils down to one thing:
Probability of dying between the ages of 40 and 65 versus the medical advancements made in 25 years.

I'll take medical advancements in 25 years, I think the probability of dying b/w 40 and 65 is pretty small.

I'll way favor 20 in a 20 vs 65 to reach 90.

Wolfram 11-30-2007 12:54 PM

Re: 40 Year Old Vs 65 Year Old American Hitting 90
 
I imagine this could be solved mathematically.

Let f(x) be a function of the average life expectancy of an american male, where x is the year.

Let g(x) be the death rate for american males in one year where x is the age.

Find out where the two functions intersect. If it's > 40 years then you chose the 65 year old.

This is probably wrong and oversimplified but someone who's better at math should be able to solve this.


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