Help with SD calculations for hand distributions
 

How do you calculate the standard deviation for, say, the number of times you will be dealt a given set of hands over a given number of deals?

Example: Standard deviation for # of times dealt AA,KK,QQ,AKs over 16k hands? Or your example, but you get the idea.

Re: Help with SD calculations for hand distributions
 

[ QUOTE ]
How do you calculate the standard deviation for, say, the number of times you will be dealt a given set of hands over a given number of deals?

Example: Standard deviation for # of times dealt AA,KK,QQ,AKs over 16k hands? Or your example, but you get the idea.

[/ QUOTE ]

SD = sqrt(npq)

where
n is the number of hands
p is the probability of getting one of the hands in question on any given hand
q = 1 - p

This is the standard deviation of the binomial distribution over which the number of these hands is distributed.

In your example, there are 22 hands in question, so p = 22/C(52,2) = 22/1326. SD = sqrt(16000 * 22/1326 * 1304/1326) =~ 16.2