Im missing $1 here help!
 

ok, so some guy came into my bar yesterday and asked me this, and for the love of all things holy i just cant figure it out for some reason... plz help.

ok so three drunks each have $10, and they want to get a bottle of wine, so they each give their $10 to another drunk to go to the bottle store to buy the wine which normally costs $30, but it's on special for $25.

So the other drunk buys the wine, pockets $2, and give the other drunks $1 back each.

So now basically the drunks have paid $9 each, and the other drunk has $2 but 9 times 3 = 27 +2 =29.. what happened to the other dollar?? [img]/images/graemlins/confused.gif[/img]

Re: Im missing $1 here help!
 

lol i thought this was gonna be spam

Re: Im missing $1 here help!
 

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lol i thought this was gonna be spam

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Re: Im missing $1 here help!
 

I don't see the puzzle here, heh.

Re: Im missing $1 here help!
 

switch doors ldo

Re: Im missing $1 here help!
 

Taxes, obv.

Damn liberals and their entitlement programs.

Re: Im missing $1 here help!
 

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switch doors ldo

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why? it's 50/50...u just like making monty work?

Re: Im missing $1 here help!
 

All right so we have 3x10=30$
Cost of wine: 25$, expected cost 30$
Money saved = 5$
Kep: 2$ to return 3$
25+2+3=30
He returns, gives every guy one back so they have payed 9$ each.
9x3+2 (money he saved) = 29.
Took me a while to figure out, results in white:
<font color="white"> You don't have to calculate 9x3=27;27+2=29 and wonder where the 1$ went. Instead you do 9x3=27;27-2$ the guy kept = 25 (what was payed for the bottle) </font>

Re: Im missing $1 here help!
 

clown,

i cant believe you took this seriously

this is like probably the oldest math puzzle ever created

Re: Im missing $1 here help!
 

[ QUOTE ]
clown,

i cant believe you took this seriously

this is like probably the oldest math puzzle ever created

[/ QUOTE ]
I figured it involves grapes, I give it a try.