Prisoner Dilemma #2

[qwnu]

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Assuming a random distribution of hats this method should set 75 prisoners free in average.

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Are we justified in doing this?

How about, if you count more of one color in front of you, say that color. If you count the same number of each, say what the guy behind you said.

Of course, if you are in position 100 and you see that 1-50 have black hats and 51-99 have white hats, you'd be a fool to say black. :-(