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#25
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[ QUOTE ] [ QUOTE ] The variance of a binomial distribution is n*P*(1-p) s.d = sqrt[n*P*(1-p)] but this assumes p is constant for each game . [/ QUOTE ] I didnt' assume that p was constant for each game. It varied between 50 and 70 percent. In my simulation, I first picked what the winrate would be, then, based on that, decided if the player won. [/ QUOTE ] but assuming u sit down first in a sng, u should calculate with p=0.6 as u dont know anything about your random opponent, dont u? sitting there with a good or bad opponent is part of luck, so your variance shouldnt be reduced if u do well vs certain opps and do bad vs others. pls correct me if i m wrong. [/ QUOTE ] Taking the average of your winrate does seems like it would reduce variance IMO but much much easier. |
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