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Well.... no.

With a VPIP of 90%, there is a 1/10 that Villain folds.

It's a little more complicated to figure out how often one of his opponents has AA-JJ, but 10% is somewhere in the neighborhood, and will make the calculations easier, and won't much effect the unlikeliness of the result.

Four possible outcomes on each hand:
Villain folds, an opponent has AA-JJ: (.1 * .1) = .01
Villain folds, an opponent doesn't have AA-JJ: (.1 * .9) = .09
Villain doesn't fold, an opponent has AA-JJ: (.9 * .1) = .09
Villain doesn't fold, an opponent doesn't have AA-JJ: (.9 * .9) = .81

Note the sum of the probabilities is 1.

Now for 25 independent events, we just multiply, so you end up with:

(.01^4) * (.81^21) = 1E-10 = 1 in 10 billion. [img]/images/graemlins/shocked.gif[/img]

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We know villain folds about 4 times in 25 hands. What are the odds that he does that exactly the four times somebodey had AA-JJ?

(4/25)*(3/24)*(2/23)*(1/22) = .16*.125*.086*.045=.0000774 =
1:112919 [img]/images/graemlins/crazy.gif[/img].

That is ofc not complete because we don't know the odds that villain would fold 4 times in 25 hands but I would say that those odds a are pretty good.

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Dude, I'm sorry, but this is out of left field.

I stand by my post, and will really have to stop there with any further odds discussions.