![]() |
|
#14
|
|||
|
|||
|
Ok, I can't stand to see incorrect answers posted, even though I maintain that this is a poor thought experiment since playing-UTG-against-cheating-idiots is so different from poker.
Let value(n) be your equity with a stack of size n. value(1)=1. The probability of winning with which you should push is value(n-1)/(2n+8), so that you are indifferent to folding to get a stack of n-1 worth value(n-1) and pushing to get a share of the 2n+8 pot. You should push with at least (value(n-1)/(2n+8))^(1/9). value(n) = value(n-1) ((value(n-1)/(2n+8))^(1/9)) + Integral (2n+8) x^9 dx from (value(n-1)/(2n+8))^(1/9) to 1. We can use this recursively to compute value(n). n value(n) ------------ 1 1 2 1.882862 3 2.755967 4 3.640068 5 4.542981 6 5.467867 7 6.415821 8 7.386923 9 8.380731 10 9.396536 11 10.433498 12 11.490724 13 12.567311 14 13.662373 15 14.775055 16 15.904540 17 17.050054 100 136.900389 1000 1755.195048 |
|
|