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I was thinking about how to calculate the EV of a bluff. I came up with this formula. Do you think it is correct?
P = Pot before you bluff B = Bet-size of the bluff FE = The percentage of the time you guess all opponents will fold to your bluff EV = Exptected value EV = -(B -(B * FE)) + (P * FE) This formula assumes you will never win any part of the pot in any other way if the bluff is called. Example: Party Poker No Limit Holdem Ring game Blinds: $5/$10 10 players Converter Stack sizes: SB: 1000$ Hero: 1000$ Pre-flop: (10 players) Hero is BB with 2[img]/images/graemlins/club.gif[/img] 3[img]/images/graemlins/diamond.gif[/img] 8 folds, SB calls 5$, Hero checks. Flop: A[img]/images/graemlins/spade.gif[/img] K[img]/images/graemlins/diamond.gif[/img] Q[img]/images/graemlins/spade.gif[/img] ($20, 2 players) SB checks, Hero bets $15, SB calls $15. Turn: 8[img]/images/graemlins/heart.gif[/img] ($60, 2 players) SB checks, Hero bets $25, SB calls $25. River: 7[img]/images/graemlins/heart.gif[/img] ($100, 2 players) SB checks, Hero bets $50 In this hand, Hero thinks the opponent will have a busted flush draw 50% of the time, in this case he will fold to Heros bluff. The remaining 50% of the time Hero thinks villain has been slow-playing a monster, and the bluff will be at least called. The opponent will therefore fold to a bet 50% of the time here. Here are the calculations: P = 100$ B = 50$ FE = 50% = 0.5 EV = -(B -(B * FE)) + (P * FE) EV = -(50$ -(50$ * 0.5)) + (100$ * 0,5) EV = -(50$ -(25$)) + (50$) EV = -(25$) + (50$) EV = 25$ In the example, your bluff will on average win you 25$, if I have gotten things right here. I just came up with this forumla and I'm not really confident with it yet. I'd appreciate if anyone in this forum has any thoughts on it. |
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