Re: October [censored] thread
We need to figure out the speed that the paddler needs to travel to go 1 hour north and then turn around and cover his previous distance + 2 miles in the time that the stream carries the log 2 miles. You figure that if the canoeist is using the same force in both directions, his speed would obviously differ depending on which way he was travelling. If we assume he'd travel a certain speed in still water, he'd theoretically travel that speed - the stream's speed when heading upstream, and that speed + the stream's speed heading downstream.
So if the stream's speed is 1 mph - the paddler's speed would need to be 3 mph...he would go 2 miles upstream in the first hour(3mph - 1mph), and then in the next hour he would come back 4 miles to catch the log - having traveled 2 miles upstream and 4 miles downstream over the course of these 2 hours. The log would travel the 2 miles over the course of 2 hours(at 1mph)
James
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