[durron597]

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I think the solution should be something like:

If the first prisoner sees an even number of black hats, he calls black. If he sees an odd number of black hats he sayas white. The second prisoner uses the info that the first prisoner saw an even/odd number of black hats to deduce his hat color and so forth.

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this is the correct answer

btw this type of thread should probably be posted in POG (either in addition to or in place of here)