Re: Prisoner Dilemma #2
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I think the solution should be something like:
If the first prisoner sees an even number of black hats, he calls black. If he sees an odd number of black hats he sayas white. The second prisoner uses the info that the first prisoner saw an even/odd number of black hats to deduce his hat color and so forth.
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Pretty sure this is correct. 99.5/100 on average go free unless I'm missing something.
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