[TrainHardDieHard]

[ QUOTE ]
[ QUOTE ]
It isn't too difficult to figure out .

If there are n players , the probability is a little less than
6*n/1326 .

[/ QUOTE ]

It depends on how you choose to look at the question. If it's like: "Wow, kings! I wonder if my opponent has aces, though...", then you'll use the formula above (which, for n=1, unsurprisingly gives .0045: the probability a player gets pocket aces).

On the other hand, if it's like "I'd like to play HU, but seems like it'll always be KK vs. AA and I just can't take that anymore", i.e. if you are only interested to find the probability that YOU get dealt kings while HE gets the rockets, I'd like to think that the math goes:

P("I get kings and he wakes up with rockets") = .0045 x .0045 = 0.00002025 (approx. one in fifty thousand).

By the way, did you manage to fail to suck out both times?

[/ QUOTE ]

-Is this method correct in solving it? this is exactly how i solved it.

(6/1326)*(6/1326) = .0000205 or .00205%.