[The4Aces]

I am not sure if this is exactly the right place to post this thread, but I am going to post it here anyways in hopes that you respond.

I would like your explanation/opinion of the “Monty Hall” problem. I am going to try to give a scenario that is represents the problem that has more to deal with gambling than the donkey/cars.

For example: If i have 3 briefcases. In one briefcase there is $1,000,000 and in the other 2 cases there is $0. I know which case has $1,000,000, but I do not care if you win the money or not.

I give you the option to choose a case. In this example you choose case #1. I then revile that case #3 is empty. I then give you the option to switch to case #2.

Is it +EV to switch to case #2? and if so why?

Most people would probably say that it doesn't matter if you switch or not. However there is a lot of math out there saying it is +EV to switch. Can you please give your opinion/ analysis of this problem?