Thread: Bill Chen Type Pure Math/Poker Problem
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Old 11-23-2006, 03:20 PM
bigpooch bigpooch is offline
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Default Re: Bill Chen Type Pure Math/Poker Problem
Right. Need the expectation of playing as greater than the
expectation of folding and the expectation of folding is
going to be (-x)(1 - z^(N-1)) and not zero.

Then, instead,

z = [ y/((N-1)x+y)]^[1/(N-1)].
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