Re: Math question: folding an underfull
My attempt at math: If I narrow him to only 1 hand that I beat and all other possible holdings that beat me discounting K8 and K2 there are
8 combinations of KQ
6 combinations of AK
1 comb. of KK
3 comb. of AA
so I beat 8, I lose to 10. Thus bad fold unless I am sure he has exactly one of the three combos that I lose to. While I still feel like he had a monster I can't discount KQ and if I did this math right the fold is stupid.
I was tired....
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