Re: Strange occurance yesterday... Odds?
The odds of getting dealt any pocket pair is equal to: (52*3)/C(52,2) or 1/8.5
The odds of the board containing both of the cards to match that pocket pair is:
2*1*C(48,3)/C(50,5)=~.016
So the odds of being dealt a pocket pair and making quads with it is eual to:
1/8.5*.016=~.002
The odds of being dealt the exact same pocket pair is equal to:
C(4,20)/C(52,2)=1/221
Once again the odds of the board containing the remaining 2 of these cards is ~.016
So the odds of being dealt a specific pocket pair and making quads with it is:
.016*1/221=~.00007
Therefore the odds of, on any two given hands, being dealt a pocket pair, making quads with it and then have the same thing happen the next hand is equal to:
.00007*.002=.0000001 or .00001%
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