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vkotlyar 03-27-2007 09:19 PM

more than a pair
 
what is the probability of flopping at lest 2 pair with a suited connector (lets take 67s). By more than a pair, i would like to exclude all flops where i flop 2 pr without using both of my cards(like 446 or 888)
thanks
V

Cobra 03-27-2007 10:46 PM

Re: more than a pair
 
I will answer the probability of hitting two pair, three of a kind, a full house or four of a kind.

Using combinations = ((6c2)*44 + (6c3)) / (50c3)

This is equal to 3.5%.

Cobra

findingneema 03-28-2007 05:09 AM

Re: more than a pair
 
To break it down (all using both hole cards):

19600 flops
2 pair: (3c1)^2(11c1)(4c1)*2 = 396 ways
trips: (3c2)(11c1)(4c1)*2 = 264 ways
full house: (3c2)(3c1)*2 = 18 ways
quads: 2 ways

sum = 680 ways / 19600 = 3.47% or 27.8 to 1

vkotlyar 03-28-2007 07:40 PM

Re: more than a pair
 
[ QUOTE ]
To break it down (all using both hole cards):

19600 flops
2 pair: (3c1)^2(11c1)(4c1)*2 = 396 ways
trips: (3c2)(11c1)(4c1)*2 = 264 ways
full house: (3c2)(3c1)*2 = 18 ways
quads: 2 ways

sum = 680 ways / 19600 = 3.47% or 27.8 to 1

[/ QUOTE ]

do those calculations include flopping two pair with a pair on the board? like a AA6 flop when you have 56
thanks
v

findingneema 03-28-2007 09:37 PM

Re: more than a pair
 
No.

That would be (3c1)*(11c1)(4c2)*2 = 396 ways or an extra 2.02%.


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