A math quicky #2

[jay_shark]

Show that the sqrt0.99999 starts off with at least 5 consecutive 9's .

[GMontag]

For 0<x<1, x<sqrt(x)<1. So sqrt(0.99999) has to be between 0.99999 and 1, and therefore has to start with at least 5 consecutive 9s.

[jay_shark]

Good job !!

[housenuts]

Start --> Run --> calc --> .99999 x^y .5 = 0.9999949999874999374996093722656