View Full Version : Tricky math factoring problem
Magic_Man
11-28-2006, 10:40 PM
Need some help with this problem from the GMATs:
For each positive integer n, the function h(n) is defined as the product of all even numbers from 2 to n inclusive.
Let p = the smallest prime factor of [h(100) + 1]. Then p is ....
a) Between 2 and 10
b) Between 10 and 20
c) Between 20 and 30
d) Between 30 and 40
e) Over 40
Not sure what to do here...I think I need to do some kind of tricky factoring:
2*4*6*...*100 + 1 = ?
Anyone have any ideas? Thanks!
~MagicMan
51cards
11-28-2006, 10:58 PM
Over 40 ftw
explination to follow
Sooga
11-28-2006, 11:00 PM
i'm probably missing something here, but i'd go with e) over 40.
2 * 4 * 6 * ... * 100 you can think of as 2 * (2*2) * (2*3) * (2*4) * ... * (2*50). So basically any whole number from 2 to 50 cannot not be a factor of h(100) + 1, since you'll always have 1 as a remainder.
So I think the smallest possible factor of h(100) + 1 is 53. Is that right? I'm just spitballin here.
51cards
11-28-2006, 11:03 PM
There really isn't that much to it.
h(100) = 2*(1*2*3*4*5...50)
So h(100) is divisible by every number between 1 and 49 (and a whole lot more)
Any number that divides h(100) cannot divide h(100) + 1
So there are no numbers, let alone prime numbers, that are below 49 and divide h(100) + 1.
edited: meh, details.
Magic_Man
11-28-2006, 11:06 PM
Ugh, that was easy. I have to go sulk in the corner now.
::sulks::
~MagicMan
PS Thanks!
felson
11-29-2006, 04:38 AM
OP, change location pls! that is embarrassing.
Magic_Man
11-29-2006, 07:39 AM
Meh, I'm in engineering. We can't bother ourselves with these trifling math exercises /images/graemlins/wink.gif
~MagicMan
thylacine
11-29-2006, 12:14 PM
[ QUOTE ]
Meh, I'm in engineering. We can't bother ourselves with these trifling math exercises /images/graemlins/wink.gif
~MagicMan
[/ QUOTE ]
Tacoma bridge, etc.
HeavilyArmed
11-29-2006, 04:12 PM
[ QUOTE ]
h(100) = 2*(1*2*3*4*5...50)
[/ QUOTE ]
h(100) = 2^50*(1*2*3*4*5...50)
I had to look at it twice to get that part right.
I looked at the possible answers and decided that >40 had to be the best guess. This is an ability most intelligent test taker have in many situations. This is a very poor question for a multiple guess test.
felson
11-30-2006, 06:29 AM
[ QUOTE ]
Meh, I'm applying for business school. We can't bother ourselves with these trifling math exercises /images/graemlins/wink.gif
[/ QUOTE ]
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