View Full Version : Two is one
a = b
aa = ab
a^2 = ab
a^2 - b^2 = ab - b^2
(a+b)(a-b) = b(a-b)
a+b = b
b+b = b ...(since a = b)
2b = b
2 = 1
What's wrong here?
Borodog
01-28-2006, 11:46 AM
You divided by zero.
soon2bepro
01-28-2006, 11:51 AM
you multiplied by zero. just because 2*0 = 0 and 1*0= 0 doesn't mean 2 = 1
Thanks guys, I knew I was missing something simple.
ihardlyknowher
01-29-2006, 03:25 AM
I don't see how:
(a+b)(a-b) = b(a-b)
Also, if a+b=b, then a by definition is zero. Thus, b=0 and you just typed:
0=0
0=0
0=0
0=0
0=0
0=0
0=0
0=0
2=1
soon2bepro
01-29-2006, 11:33 AM
say a = 1
(a+a)(a-a) = a(a-a)
(1+1)(1-1) = 1(1-1)
2*0 = 1*0
0 = 0
the problem here, is that ANYTHING * a-a = 0.
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